What is the tangent of y=sin(xy)+pi,(1,pi) ?

The tangent of y=sin(xy)+pi,(1,pi) is y=-pi/2 x+pi+pi/2

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tangent of y=sin(xy)+pi,(1,pi)

tangent of

y = sin (x y) + π, (1, π)

y = - \frac{π}{2} x + π + \frac{π}{2}

Solution steps

Find the slope of

y = sin (x y) + π : \frac{d y}{d x} = \frac{y cos ( x y )}{1 - x cos ( x y )}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{π}{2}

Find the line with slope m=

- \frac{π}{2}

and passing through

(1, π) : y = - \frac{π}{2} x + π + \frac{π}{2}

y = - \frac{π}{2} x + π + \frac{π}{2}

7 \frac{d ^{2} y}{d x ^{2}} + 4 \frac{d y}{d x} + 9 y = 0

f (x) = x^{4} + 3 x^{2} - x, (1, 3)

\int_{0}^{a} x d x

\int_{0}^{1} 6 x^{2} + 4 x - 3 + 4 e^{4 x} d x

y^{^{''}} - 5 y^{^{'}} + 6 y = 2 e^{t}

What is the tangent of y=sin(xy)+pi,(1,pi) ?
The tangent of y=sin(xy)+pi,(1,pi) is y=-pi/2 x+pi+pi/2