What is the integral from 0 to a of x ?

The integral from 0 to a of x is (a^2)/2

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integral from 0 to a of x

\int_{0}^{a} x d x

\frac{a ^{2}}{2}

Solution steps

\int_{0}^{a} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0}^{a}

= [\frac{x ^{2}}{2}]_{0}^{a}

Compute the boundaries:

\frac{a ^{2}}{2}

= \frac{a ^{2}}{2}

\int_{0}^{1} 6 x^{2} + 4 x - 3 + 4 e^{4 x} d x

y^{^{''}} - 5 y^{^{'}} + 6 y = 2 e^{t}

(5, 2), (2, - 3)

\frac{d}{d x} (\frac{x}{x ^{4} + 1})

y = (x^{3} - 16 x)^{14}, (4, 0)

What is the integral from 0 to a of x ?
The integral from 0 to a of x is (a^2)/2