What is the tangent of f(x)=x^4+2x^2-x,(1,2) ?

The tangent of f(x)=x^4+2x^2-x,(1,2) is y=7x-5

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tangent of f(x)=x^4+2x^2-x,(1,2)

tangent of

f (x) = x^{4} + 2 x^{2} - x, (1, 2)

y = 7 x - 5

Solution steps

Find the slope of

f (x) = x^{4} + 2 x^{2} - x : \frac{df ( x )}{d x} = 4 x^{3} + 4 x - 1

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 7

Find the line with slope m=

7

and passing through

(1, 2) : y = 7 x - 5

y = 7 x - 5

\frac{d}{d x} (x, x^{2} - y, x + y^{2})

\int \frac{5}{( 8 z - 1 ) ^{\frac{7}{8}}} d z

e^{2} + ln (4)

x \to 0 - lim (\frac{1}{x})

x \to 2 lim (\frac{x - 2}{4 - x ^{2}})

What is the tangent of f(x)=x^4+2x^2-x,(1,2) ?
The tangent of f(x)=x^4+2x^2-x,(1,2) is y=7x-5