What is the integral from 0 to infinity of 12e^{-4x} ?

The integral from 0 to infinity of 12e^{-4x} is 3

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integral from 0 to infinity of 12e^{-4x}

\int_{0}^{\infty} 12 e^{- 4 x} d x

3

Solution steps

\int_{0}^{\infty} 12 e^{- 4 x} d x

Compute the indefinite integral:

\int 12 e^{- 4 x} d x = - 3 e^{- 4 x} + C

Compute the boundaries:

\int_{0}^{\infty} 12 e^{- 4 x} d x = 0 - (- 3)

= 0 - (- 3)

Simplify

= 3

5 y ln (x) - x y^{^{'}} = 0

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\frac{\partial}{\partial y} (- e^{- x} z cos (y))

(x^{2} \cdot 2^{x})^{7}

\frac{1}{5 u ^{5}}

What is the integral from 0 to infinity of 12e^{-4x} ?
The integral from 0 to infinity of 12e^{-4x} is 3