What is the derivative of ((e^x))/(5x^2) ?

The derivative of ((e^x))/(5x^2) is (e^x(x-2))/(5x^3)

What is the first derivative of ((e^x))/(5x^2) ?

The first derivative of ((e^x))/(5x^2) is (e^x(x-2))/(5x^3)

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derivative of

\frac{( e ^{x} )}{5 x ^{2}}

\frac{e ^{x} ( x - 2 )}{5 x ^{3}}

Solution steps

\frac{d}{d x} (\frac{e ^{x}}{5 x ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{5} \frac{d}{d x} (\frac{e ^{x}}{x ^{2}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{1}{5} \cdot \frac{\frac{d}{d x} ( e ^{x} ) x ^{2} - \frac{d}{d x} ( x ^{2} ) e ^{x}}{( x ^{2} ) ^{2}}

\frac{d}{d x} (e^{x}) = e^{x}

\frac{d}{d x} (x^{2}) = 2 x

= \frac{1}{5} \cdot \frac{e ^{x} x ^{2} - 2 x e ^{x}}{( x ^{2} ) ^{2}}

Simplify

\frac{1}{5} \cdot \frac{e ^{x} x ^{2} - 2 x e ^{x}}{( x ^{2} ) ^{2}} : \frac{e ^{x} ( x - 2 )}{5 x ^{3}}

= \frac{e ^{x} ( x - 2 )}{5 x ^{3}}

\frac{1}{s ( s + 1 ) ( s + 5 )}

- 3 (t - 1)

y^{^{'}} = - 4 y + 57

e^{x} d x - y d y = 0, y (0) = 1

\int_{1}^{3} \frac{4}{x ^{2} + 1} d x

What is the derivative of ((e^x))/(5x^2) ?
The derivative of ((e^x))/(5x^2) is (e^x(x-2))/(5x^3)
What is the first derivative of ((e^x))/(5x^2) ?
The first derivative of ((e^x))/(5x^2) is (e^x(x-2))/(5x^3)