What is the derivative of y=e^x+x^2 ?

The derivative of y=e^x+x^2 is e^x+2x

What is the first derivative of y=e^x+x^2 ?

The first derivative of y=e^x+x^2 is e^x+2x

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derivative of

y = e^{x} + x^{2}

e^{x} + 2 x

Solution steps

\frac{d}{d x} (e^{x} + x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (e^{x}) + \frac{d}{d x} (x^{2})

\frac{d}{d x} (e^{x}) = e^{x}

\frac{d}{d x} (x^{2}) = 2 x

= e^{x} + 2 x

\int \frac{5 e ^{x}}{e ^{2 x} + 2 e ^{x} + 1} d x

(- 4, 0), (1, - 5)

\frac{d}{d x} (x^{2} + 2 y^{2} - 4)

(y - x) d x + 4 x d y = 0

\int \frac{1}{2 x - 1} d x

What is the derivative of y=e^x+x^2 ?
The derivative of y=e^x+x^2 is e^x+2x
What is the first derivative of y=e^x+x^2 ?
The first derivative of y=e^x+x^2 is e^x+2x