What is the solution for (dy)/(dx)=((x+y))/(3x+3y-4) ?

The solution for (dy)/(dx)=((x+y))/(3x+3y-4) is y=-(\W(-3/(4e^{4x+c_{1)-3}}))/3+1-x

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(dy)/(dx)=((x+y))/(3x+3y-4)

\frac{d y}{d x} = \frac{( x + y )}{3 x + 3 y - 4}

y = - \frac{W ( - \frac{3}{4 e ^{4 x + c_{1} - 3}} )}{3} + 1 - x

Solution steps

\frac{d y}{d x} = \frac{( x + y )}{3 x + 3 y - 4}

Solve using substitution:

y = - \frac{W ( - \frac{3}{4 e ^{4 x + c_{1} - 3}} )}{3} + 1 - x

y = - \frac{W ( - \frac{3}{4 e ^{4 x + c_{1} - 3}} )}{3} + 1 - x

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What is the solution for (dy)/(dx)=((x+y))/(3x+3y-4) ?
The solution for (dy)/(dx)=((x+y))/(3x+3y-4) is y=-(\W(-3/(4e^{4x+c_{1)-3}}))/3+1-x