What is (\partial)/(\partial x)(-2/3 x-1/3 y+2) ?

The answer to (\partial)/(\partial x)(-2/3 x-1/3 y+2) is -2/3

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(\partial)/(\partial x)(-2/3 x-1/3 y+2)

\frac{\partial}{\partial x} (- \frac{2}{3} x - \frac{1}{3} y + 2)

- \frac{2}{3}

Solution steps

\frac{\partial}{\partial x} (- \frac{2}{3} x - \frac{1}{3} y + 2)

Simplify

- \frac{2}{3} x - \frac{1}{3} y + 2 : \frac{- 2 x - y}{3} + 2

= \frac{\partial}{\partial x} (\frac{- 2 x - y}{3} + 2)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (\frac{- 2 x - y}{3}) + \frac{\partial}{\partial x} (2)

\frac{\partial}{\partial x} (\frac{- 2 x - y}{3}) = - \frac{2}{3}

\frac{\partial}{\partial x} (2) = 0

= - \frac{2}{3} + 0

Simplify

= - \frac{2}{3}

x + e^{x} - \frac{1}{x}

\int e^{x} (x + 1) d x

\frac{\partial}{\partial x} (8 x e^{x y})

\frac{\partial}{\partial x} (\frac{( x - q )}{y} \cdot q)

\int_{1}^{16} x d x

What is (\partial)/(\partial x)(-2/3 x-1/3 y+2) ?
The answer to (\partial)/(\partial x)(-2/3 x-1/3 y+2) is -2/3