What is the tangent of arcsin(x/7),\at x=4 ?

The tangent of arcsin(x/7),\at x=4 is y= 1/(sqrt(33))x+arcsin(4/7)-4/(sqrt(33))

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tangent of arcsin(x/7),\at x=4

tangent of

arcsin (\frac{x}{7}), at x = 4

y = \frac{1}{33} x + arcsin (\frac{4}{7}) - \frac{4}{33}

Solution steps

Find the tangent point:

(4, arcsin (\frac{4}{7}))

Find the slope of

y = arcsin (\frac{x}{7}) : \frac{d y}{d x} = \frac{1}{49 - x ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{1}{33}

Find the line with slope m=

\frac{1}{33}

and passing through

(4, arcsin (\frac{4}{7})) : y = \frac{1}{33} x + arcsin (\frac{4}{7}) - \frac{4}{33}

y = \frac{1}{33} x + arcsin (\frac{4}{7}) - \frac{4}{33}

\frac{d}{d x} (ln (8 - 9 x))

y^{^{''}} + 4 y = t sin (2 t)

\frac{d y}{d x} + 12 y = 7

\frac{\partial}{\partial x} (\frac{x}{y} + \frac{y}{z})

\int 3 x 3 - 3 x d x

What is the tangent of arcsin(x/7),\at x=4 ?
The tangent of arcsin(x/7),\at x=4 is y= 1/(sqrt(33))x+arcsin(4/7)-4/(sqrt(33))