What is the solution for (x^2+1)(dy)/(dx)+3x(y-1)=0,y(0)=8 ?

The solution for (x^2+1)(dy)/(dx)+3x(y-1)=0,y(0)=8 is y= 7/((x^2+1)^{3/2)}+1

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(x^2+1)(dy)/(dx)+3x(y-1)=0,y(0)=8

(x^{2} + 1) \frac{d y}{d x} + 3 x (y - 1) = 0, y (0) = 8

y = \frac{7}{( x ^{2} + 1 ) ^{\frac{3}{2}}} + 1

Solution steps

(x^{2} + 1) \frac{d y}{d x} + 3 x (y - 1) = 0

Solve separable ODE:

y = \frac{7}{( x ^{2} + 1 ) ^{\frac{3}{2}}} + 1

y = \frac{7}{( x ^{2} + 1 ) ^{\frac{3}{2}}} + 1

\int (x^{5} - 2 x^{3}) d x

y = lo g_{2} (x^{2} - 5 x)

\frac{d}{d x} (arctan (\frac{x}{6}))

\int x ln (8 x) d x

y^{'} = 0.0016 y (2500 - y)

What is the solution for (x^2+1)(dy)/(dx)+3x(y-1)=0,y(0)=8 ?
The solution for (x^2+1)(dy)/(dx)+3x(y-1)=0,y(0)=8 is y= 7/((x^2+1)^{3/2)}+1