What is the derivative of y^2-x^2 ?

The derivative of y^2-x^2 is 2y(dy)/(dx)-2x

What is the first derivative of y^2-x^2 ?

The first derivative of y^2-x^2 is 2y(dy)/(dx)-2x

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\frac{d}{d x} (y^{2} - x^{2})

2 y \frac{d y}{d x} - 2 x

Solution steps

\frac{d}{d x} (y^{2} - x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (y^{2}) - \frac{d}{d x} (x^{2})

\frac{d}{d x} (y^{2}) = 2 y \frac{d y}{d x}

\frac{d}{d x} (x^{2}) = 2 x

= 2 y \frac{d y}{d x} - 2 x

\frac{\partial}{\partial x} (x^{0.25} y^{0.5})

\frac{d y}{d x} = x - 3

cos (8 t + 2 π)

\int 7 tan^{3} (x) sec^{3} (x) d x

\int x (2 x + 1)^{2} d x

What is the derivative of y^2-x^2 ?
The derivative of y^2-x^2 is 2y(dy)/(dx)-2x
What is the first derivative of y^2-x^2 ?
The first derivative of y^2-x^2 is 2y(dy)/(dx)-2x