What is laplacetransform cos(8t+2pi) ?

The answer to laplacetransform cos(8t+2pi) is s/(s^2+64)

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laplacetransform cos(8t+2pi)

laplace transform

cos (8 t + 2 π)

\frac{s}{s ^{2} + 64}

Solution steps

L {cos (8 t + 2 π)}

Use Laplace Transform table:

L {cos (a t + b)} = \frac{s \cdot cos ( b ) - a \cdot sin ( b )}{s ^{2} + a ^{2}}

L {cos (8 t + 2 π)} = \frac{s cos ( 2 π ) - 8 sin ( 2 π )}{s ^{2} + 8 ^{2}}

= \frac{s cos ( 2 π ) - 8 sin ( 2 π )}{s ^{2} + 8 ^{2}}

= \frac{s}{s ^{2} + 64}

\int 7 tan^{3} (x) sec^{3} (x) d x

\int x (2 x + 1)^{2} d x

f (x) = x^{2} + 4, (4, 20)

x \to 2 - lim (e^{\frac{1}{x - 2}})

y^{^{'}} = y (\frac{1}{x} - y)

What is laplacetransform cos(8t+2pi) ?
The answer to laplacetransform cos(8t+2pi) is s/(s^2+64)