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Popular >

y^'=y(1/x-y)

Solution

y^{^{'}} = y (\frac{1}{x} - y)

Solution

y = \frac{2 x}{x ^{2} + c _{1}}

Solution steps

y^{'} (x) = y (\frac{1}{x} - y)

Solve Bernoulli ODE:

y = \frac{2 x}{x ^{2} + c _{1}}

y = \frac{2 x}{x ^{2} + c _{1}}

Graph

Popular Examples

area y=x^2-4x-5,y=2x-5 area

y = x^{2} - 4 x - 5, y = 2 x - 5

integral from 2.25 to 2.75 of 2

\int_{2.25}^{2.75} 2 d x

derivative of arctan(3x^2-x)

\frac{d}{d x} (arctan (3 x^{2} - x))

integral from-infinity to 1 of 1/(x^2)

\int_{- \infty}^{1} \frac{1}{x ^{2}} d x

integral from 0 to 6 of pi(-x^2+6x)

\int_{0}^{6} π (- x^{2} + 6 x) d x

Frequently Asked Questions (FAQ)

What is the solution for y^'=y(1/x-y) ?
The solution for y^'=y(1/x-y) is y=(2x)/(x^2+c_{1)}