What is the slope of 2-3/(x^2),\at x=1 ?

The slope of 2-3/(x^2),\at x=1 is 6

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slope of 2-3/(x^2),\at x=1

slope

2 - \frac{3}{x ^{2}}, at x = 1

6

Solution steps

y = 2 - \frac{3}{x ^{2}}

In order to find the slope of the function, take the derivative of

2 - \frac{3}{x ^{2}}

\frac{d}{d x} (2 - \frac{3}{x ^{2}}) = \frac{6}{x ^{3}}

\frac{6}{x ^{3}}

Find the value of

\frac{6}{x ^{3}}

for

x = 1 : 6

6

f (x) = \frac{7}{x}, (1, 7)

x \to 0 + lim (x - ln (x))

\frac{\partial}{\partial x} (\frac{x ^{3}}{1 - x ^{2}})

\int_{- π}^{π} sin (x) cos (n x) d x

2 t (\frac{d y}{d t}) + y = 4 t^{2} + 3 t