What is the derivative of 2cos^3(t) ?

The derivative of 2cos^3(t) is -6cos^2(t)sin(t)

What is the first derivative of 2cos^3(t) ?

The first derivative of 2cos^3(t) is -6cos^2(t)sin(t)

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derivative of

2 cos^{3} (t)

- 6 cos^{2} (t) sin (t)

Solution steps

\frac{d}{d t} (2 cos^{3} (t))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d t} (cos^{3} (t))

Apply the chain rule:

3 (cos (t))^{2} \frac{d}{d t} (cos (t))

= 3 (cos (t))^{2} \frac{d}{d t} (cos (t))

\frac{d}{d t} (cos (t)) = - sin (t)

= 2 \cdot 3 (cos (t))^{2} (- sin (t))

Simplify

= - 6 cos^{2} (t) sin (t)

\int e^{\frac{1}{3} x} d x

x \to - 2 + lim (x + 2)

\frac{d}{d x} (\frac{x}{1 - ln ( x - 1 )})

f (x) = 2 + 4 x^{2}, (0, 2)

y = \frac{8}{sin ( x ) + cos ( x )}, (0, 8)

What is the derivative of 2cos^3(t) ?
The derivative of 2cos^3(t) is -6cos^2(t)sin(t)
What is the first derivative of 2cos^3(t) ?
The first derivative of 2cos^3(t) is -6cos^2(t)sin(t)