What is the tangent of y= 8/(sin(x)+cos(x)),(0,8) ?

The tangent of y= 8/(sin(x)+cos(x)),(0,8) is y=-8x+8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of y= 8/(sin(x)+cos(x)),(0,8)

tangent of

y = \frac{8}{sin ( x ) + cos ( x )}, (0, 8)

y = - 8 x + 8

Solution steps

Find the slope of

y = \frac{8}{sin ( x ) + cos ( x )} : \frac{d y}{d x} = - \frac{8 ( cos ( x ) - sin ( x ) )}{1 + sin ( 2 x )}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 8

Find the line with slope m=

- 8

and passing through

(0, 8) : y = - 8 x + 8

y = - 8 x + 8

\frac{\partial}{\partial x} (\frac{3 x - y}{x + 2 y})

\int \frac{cos ( x )}{sin ( x ) + sin ^{2} ( x )} d x

y^{^{''}} + 34 y = 0

d x + d y e^{6 x} = 0

f (x) = e^{1}

What is the tangent of y= 8/(sin(x)+cos(x)),(0,8) ?
The tangent of y= 8/(sin(x)+cos(x)),(0,8) is y=-8x+8