What is the d/(dt)(t-sin(t)) ?

The d/(dt)(t-sin(t)) is 1-cos(t)

What is the first d/(dt)(t-sin(t)) ?

The first d/(dt)(t-sin(t)) is 1-cos(t)

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\frac{d}{d t} (t - sin (t))

1 - cos (t)

Solution steps

\frac{d}{d t} (t - sin (t))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d t}{d t} - \frac{d}{d t} (sin (t))

\frac{d t}{d t} = 1

\frac{d}{d t} (sin (t)) = cos (t)

= 1 - cos (t)

\frac{\partial}{\partial y} (sin (x + y) + (x + y))

x^{2} y \frac{d y}{d x} = e^{x}

n = 1 \sum \infty \frac{3}{n}

\int 9 4 - x^{2} d x

(\frac{1}{x ln ( x )})^{^{'}}