What is the sum from n=0 to infinity of (-1)^n2^n ?

The sum from n=0 to infinity of (-1)^n2^n is diverges

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sum from n=0 to infinity of (-1)^n2^n

n = 0 \sum \infty (- 1)^{n} 2^{n}

diverges

Solution steps

n = 0 \sum \infty (- 1)^{n} \cdot 2^{n}

Apply Series Ratio Test:

diverges

= diverges

\int \frac{1}{t ^{2} 121 - t ^{2}} d t

\int e^{2 x} \cdot x^{2} d x

\frac{\partial}{\partial x} (4 (y^{2} - x^{2}) ln (x + y))

\int x^{2} \cdot 1 - x d x

\frac{1}{2 x} - \frac{8}{5 x ^{4}}

What is the sum from n=0 to infinity of (-1)^n2^n ?
The sum from n=0 to infinity of (-1)^n2^n is diverges