What is the limit as x approaches-3 of ((x^2+7x+12))/(x^2-9) ?

The limit as x approaches-3 of ((x^2+7x+12))/(x^2-9) is -1/6

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limit as x approaches-3 of ((x^2+7x+12))/(x^2-9)

x \to - 3 lim (\frac{( x ^{2} + 7 x + 12 )}{x ^{2} - 9})

- \frac{1}{6}

Decimal

- 0.16666 \dots

Solution steps

x \to - 3 lim (\frac{x ^{2} + 7 x + 12}{x ^{2} - 9})

Simplify

\frac{x ^{2} + 7 x + 12}{x ^{2} - 9} : \frac{x + 4}{x - 3}

= x \to - 3 lim (\frac{x + 4}{x - 3})

Plug in the value

x = - 3

= \frac{- 3 + 4}{- 3 - 3}

Simplify

= - \frac{1}{6}

x \to 3 lim (\frac{x ^{2} - 9}{x + 1})

\int 4 cos (6 x) d x

\int - \frac{3 x}{2} d x

\int \frac{2}{x ^{3} + x} d x

\int_{0}^{2} 4 - x^{2} d x

What is the limit as x approaches-3 of ((x^2+7x+12))/(x^2-9) ?
The limit as x approaches-3 of ((x^2+7x+12))/(x^2-9) is -1/6