What is the integral of (e^{2t})/(sqrt(e^{2t)+4)} ?

The integral of (e^{2t})/(sqrt(e^{2t)+4)} is sqrt(e^{2t)+4}+C

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integral of (e^{2t})/(sqrt(e^{2t)+4)}

\int \frac{e ^{2 t}}{e ^{2 t} + 4} d t

e^{2 t} + 4 + C

Solution steps

\int \frac{e ^{2 t}}{e ^{2 t} + 4} d t

Apply u-substitution

: \int \frac{1}{2 u} d u

= \int \frac{1}{2 u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int \frac{1}{u} d u

Apply the Power Rule

: 2 u^{\frac{1}{2}}

= \frac{1}{2} \cdot 2 u^{\frac{1}{2}}

Substitute back

u = e^{2 t} + 4

= \frac{1}{2} \cdot 2 (e^{2 t} + 4)^{\frac{1}{2}}

Simplify

\frac{1}{2} \cdot 2 (e^{2 t} + 4)^{\frac{1}{2}} : e^{2 t} + 4

= e^{2 t} + 4

Add a constant to the solution

= e^{2 t} + 4 + C

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What is the integral of (e^{2t})/(sqrt(e^{2t)+4)} ?
The integral of (e^{2t})/(sqrt(e^{2t)+4)} is sqrt(e^{2t)+4}+C