What is the integral from-infinity to 15 of re^{r/5} ?

The integral from-infinity to 15 of re^{r/5} is 50e^3

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integral from-infinity to 15 of re^{r/5}

\int_{- \infty}^{15} r e^{\frac{r}{5}} d r

50 e^{3}

Decimal

1004.27684 \dots

Solution steps

\int_{- \infty}^{15} r e^{\frac{r}{5}} d r

Compute the indefinite integral:

\int r e^{\frac{r}{5}} d r = 5 e^{\frac{r}{5}} r - 25 e^{\frac{r}{5}} + C

Compute the boundaries:

\int_{- \infty}^{15} r e^{\frac{r}{5}} d r = 50 e^{3} - 0

= 50 e^{3} - 0

Simplify

= 50 e^{3}

\frac{d}{d x} (3 x^{2} + 8)

\int_{- 1}^{2} (3 x^{2} + 2) d x

x \to \frac{1}{3} x lim (sin (x))

y^{^{'}} = e^{2 x - y}

2 x^{2} + 2 x

What is the integral from-infinity to 15 of re^{r/5} ?
The integral from-infinity to 15 of re^{r/5} is 50e^3