What is the solution for (dy)/(dx)+2y=e^xy^{-6} ?

The solution for (dy)/(dx)+2y=e^xy^{-6} is y=\sqrt[7]{(7e^{15x}+c_{1})/(15e^{14x)}}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy)/(dx)+2y=e^xy^{-6}

\frac{d y}{d x} + 2 y = e^{x} y^{- 6}

y = 7 \frac{7 e ^{15 x} + c _{1}}{15 e ^{14 x}}

Solution steps

\frac{d y}{d x} + 2 y = e^{x} y^{- 6}

Solve Bernoulli ODE:

y = 7 \frac{7 e ^{15 x} + c _{1}}{15 e ^{14 x}}

y = 7 \frac{7 e ^{15 x} + c _{1}}{15 e ^{14 x}}

\int \frac{( ln ( x ) ) 2}{x} d x

\int_{0}^{\frac{π}{2}} e^{s i n (5 π x)} cos (5 π x) d x

\int 2 x (x^{2} + 6)^{7} d x

{\frac{1}{4 s + 1}}

\int (5 sec (x) - cos (x))^{2} d x

What is the solution for (dy)/(dx)+2y=e^xy^{-6} ?
The solution for (dy)/(dx)+2y=e^xy^{-6} is y=\sqrt[7]{(7e^{15x}+c_{1})/(15e^{14x)}}