What is the tangent of y=2x^2-6x+6,(1,2) ?

The tangent of y=2x^2-6x+6,(1,2) is y=-2x+4

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tangent of y=2x^2-6x+6,(1,2)

tangent of

y = 2 x^{2} - 6 x + 6, (1, 2)

y = - 2 x + 4

Solution steps

Find the slope of

y = 2 x^{2} - 6 x + 6 : \frac{d y}{d x} = 4 x - 6

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 2

Find the line with slope m=

- 2

and passing through

(1, 2) : y = - 2 x + 4

y = - 2 x + 4

\int a^{4 x} d x

\frac{d}{d x} (sin (3 x^{2} - 1))

x \to 0 lim ((1 + x)^{\frac{1}{3 x}})

y = 3 x + 3 x

\frac{d y}{d x} + y = e^{x} y^{- 2}

What is the tangent of y=2x^2-6x+6,(1,2) ?
The tangent of y=2x^2-6x+6,(1,2) is y=-2x+4