What is the d/(d{y)}({x}{y}{z}^2) ?

The d/(d{y)}({x}{y}{z}^2) is {x}{z}^2

What is the first d/(d{y)}({x}{y}{z}^2) ?

The first d/(d{y)}({x}{y}{z}^2) is {x}{z}^2

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\frac{d}{d y} (x y z^{2})

x z^{2}

Solution steps

\frac{d}{d y} (x y z^{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= x z^{2} \frac{d}{d y} (y)

Apply the common derivative:

\frac{d}{d y} (y) = 1

= x z^{2} \cdot 1

Simplify

= x z^{2}

f (w) = \frac{( 2 w ^{4} - 5 w )}{9 w}

\frac{d}{d x} (\frac{x ^{2} - 1}{x ^{2} + 1})

\int 2 t - 4 d t

f (t) = 2 e^{- t} cos (4 t) 1 (t)

\frac{d y}{d x} = (2 y + 1 cos (x))

What is the d/(d{y)}({x}{y}{z}^2) ?
The d/(d{y)}({x}{y}{z}^2) is {x}{z}^2
What is the first d/(d{y)}({x}{y}{z}^2) ?
The first d/(d{y)}({x}{y}{z}^2) is {x}{z}^2