What is the solution for y^'=(3x^7e^{y/x}+x^5y^2)/(x^6y) ?

The solution for y^'=(3x^7e^{y/x}+x^5y^2)/(x^6y) is y=-\W((3ln(x)+c_{1})/e)x-x

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y^'=(3x^7e^{y/x}+x^5y^2)/(x^6y)

y^{^{'}} = \frac{3 x ^{7} e ^{\frac{y}{x}} + x ^{5} y ^{2}}{x ^{6} y}

y = - W (\frac{3 ln ( x ) + c _{1}}{e}) x - x

Solution steps

y^{'} (x) = \frac{3 x ^{7} e ^{\frac{y}{x}} + x ^{5} y ^{2}}{x ^{6} y}

Solve using substitution:

y = - W (\frac{3 ln ( x ) + c _{1}}{e}) x - x

y = - W (\frac{3 ln ( x ) + c _{1}}{e}) x - x

x \to 2 lim (\frac{x - 7}{x + 3})

\int_{1}^{\infty} \frac{1}{x ^{3} - 1} d x

\int y x + y^{2} d x

\int (3 sec (x) - cos (x))^{2} d x

x^{2} - 4 x + 39

What is the solution for y^'=(3x^7e^{y/x}+x^5y^2)/(x^6y) ?
The solution for y^'=(3x^7e^{y/x}+x^5y^2)/(x^6y) is y=-\W((3ln(x)+c_{1})/e)x-x