What is the solution for (dy)/(dx)=((x^2+y^2))/(2xy) ?

The solution for (dy)/(dx)=((x^2+y^2))/(2xy) is y=sqrt(x^2+c_{1)x},y=-sqrt(x^2+c_{1)x}

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(dy)/(dx)=((x^2+y^2))/(2xy)

\frac{d y}{d x} = \frac{( x ^{2} + y ^{2} )}{2 x y}

y = x^{2} + c_{1} x, y = - x^{2} + c_{1} x

Solution steps

\frac{d y}{d x} = \frac{( x ^{2} + y ^{2} )}{2 x y}

Solve Bernoulli ODE:

y = x^{2} + c_{1} x, y = - x^{2} + c_{1} x

y = x^{2} + c_{1} x, y = - x^{2} + c_{1} x

y^{^{''}} - y = \frac{e ^{x}}{e ^{x} + 1}

\frac{d}{d x} (ln (\frac{x + 1}{x - 2}))

\int_{1}^{\infty} \frac{5}{x ^{4}} d x

\int (2 - x) d x

x \to 0 + lim (x^{\frac{1}{2}})

What is the solution for (dy)/(dx)=((x^2+y^2))/(2xy) ?
The solution for (dy)/(dx)=((x^2+y^2))/(2xy) is y=sqrt(x^2+c_{1)x},y=-sqrt(x^2+c_{1)x}