What is the integral from 1 to infinity of 5/(x^4) ?

The integral from 1 to infinity of 5/(x^4) is 5/3

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integral from 1 to infinity of 5/(x^4)

\int_{1}^{\infty} \frac{5}{x ^{4}} d x

\frac{5}{3}

Decimal

1.66666 \dots

Solution steps

\int_{1}^{\infty} \frac{5}{x ^{4}} d x

Compute the indefinite integral:

\int \frac{5}{x ^{4}} d x = - \frac{5}{3 x ^{3}} + C

Compute the boundaries:

\int_{1}^{\infty} \frac{5}{x ^{4}} d x = 0 - (- \frac{5}{3})

= 0 - (- \frac{5}{3})

Simplify

= \frac{5}{3}

\int (2 - x) d x

x \to 0 + lim (x^{\frac{1}{2}})

y^{^{'}} = \frac{( x ^{3} + y ^{3} )}{x y ^{2}}

4 y^{^{'}} + t y = 7

\frac{d ^{2}}{d x ^{2}} (9 - x^{2})

What is the integral from 1 to infinity of 5/(x^4) ?
The integral from 1 to infinity of 5/(x^4) is 5/3