What is the solution for y^'=((x^3+y^3))/(xy^2) ?

The solution for y^'=((x^3+y^3))/(xy^2) is y=x\sqrt[3]{3ln(x)+c_{1}}

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y^'=((x^3+y^3))/(xy^2)

y^{^{'}} = \frac{( x ^{3} + y ^{3} )}{x y ^{2}}

y = x 3 3 ln (x) + c_{1}

Solution steps

y^{'} (x) = \frac{( x ^{3} + y ^{3} )}{x y ^{2}}

Solve Bernoulli ODE:

y = x 3 3 ln (x) + c_{1}

y = x 3 3 ln (x) + c_{1}

4 y^{^{'}} + t y = 7

\frac{d ^{2}}{d x ^{2}} (9 - x^{2})

\int - x^{4} d x

\frac{3 x + 1}{x ^{2} + 2 x + 2}

x \to 0 lim (x - 2)

What is the solution for y^'=((x^3+y^3))/(xy^2) ?
The solution for y^'=((x^3+y^3))/(xy^2) is y=x\sqrt[3]{3ln(x)+c_{1}}