What is (\partial)/(\partial x)(2x^2) ?

The answer to (\partial)/(\partial x)(2x^2) is 4x

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(\partial)/(\partial x)(2x^2)

\frac{\partial}{\partial x} (2 x^{2})

4 x

Solution steps

\frac{\partial}{\partial x} (2 x^{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{\partial}{\partial x} (x^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 \cdot 2 x^{2 - 1}

Simplify

= 4 x

\frac{d y}{d x} = sin (2 x) - y cos (x)

\frac{d}{d x} (3 x^{4} - 4 x^{3} - 12 x^{2} + 1)

\int \frac{x ^{2} + 4 x + 10}{x ^{3} + 2 x ^{2} + 5 x} d x

\frac{d}{d x} (ln (x (1 - x)))

ln (X^{\frac{1}{2}})

What is (\partial)/(\partial x)(2x^2) ?
The answer to (\partial)/(\partial x)(2x^2) is 4x