What is the derivative of e^{x^3+4x} ?

The derivative of e^{x^3+4x} is e^{x^3+4x}(3x^2+4)

What is the first derivative of e^{x^3+4x} ?

The first derivative of e^{x^3+4x} is e^{x^3+4x}(3x^2+4)

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\frac{d}{d x} (e^{x^{3} + 4 x})

e^{x^{3} + 4 x} (3 x^{2} + 4)

Solution steps

\frac{d}{d x} (e^{x^{3} + 4 x})

Apply the chain rule:

e^{x^{3} + 4 x} \frac{d}{d x} (x^{3} + 4 x)

= e^{x^{3} + 4 x} \frac{d}{d x} (x^{3} + 4 x)

\frac{d}{d x} (x^{3} + 4 x) = 3 x^{2} + 4

= e^{x^{3} + 4 x} (3 x^{2} + 4)

\int \frac{x ^{2} - 361}{x} d x

\int_{0}^{2} 36 x + 145 d x

t^{2} + 6 t - 17

\frac{\partial}{\partial x} (- \frac{x}{( x + y ) ^{2}})

\int_{0}^{+ oo} x \cdot (x + 1)^{- 2} d x

What is the derivative of e^{x^3+4x} ?
The derivative of e^{x^3+4x} is e^{x^3+4x}(3x^2+4)
What is the first derivative of e^{x^3+4x} ?
The first derivative of e^{x^3+4x} is e^{x^3+4x}(3x^2+4)