What is the limit as x approaches-1-of (x-1)/(x+1) ?

The limit as x approaches-1-of (x-1)/(x+1) is infinity

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limit as x approaches-1-of (x-1)/(x+1)

x \to - 1 - lim (\frac{x - 1}{x + 1})

\infty

Solution steps

x \to - 1 - lim (\frac{x - 1}{x + 1})

\frac{x - 1}{x + 1} = (x - 1) \frac{1}{x + 1}

= x \to - 1 - lim ((x - 1) \frac{1}{x + 1})

x \to a lim [f (x) \cdot g (x)] = x \to a lim f (x) \cdot x \to a lim g (x)

With the exception of indeterminate form

= x \to - 1 - lim (x - 1) \cdot x \to - 1 - lim (\frac{1}{x + 1})

x \to - 1 - lim (x - 1) = - 2

x \to - 1 - lim (\frac{1}{x + 1}) = - \infty

= (- 2) (- \infty)

Apply Infinity Property:

- c \cdot (- \infty) = \infty

= \infty

\int_{0}^{\frac{1}{2}} cos (π x) d x

(2 x y + 3 y^{2}) d x - (x^{2} + 2 x y) d y = 0

f (x) = 34 x - 16 x^{2}, at x = 1

10 e^{10 x}

\frac{\partial}{\partial m} (\frac{G ( m , r ) m}{r ^{2}})

What is the limit as x approaches-1-of (x-1)/(x+1) ?
The limit as x approaches-1-of (x-1)/(x+1) is infinity