What is the solution for (dy}{dx}=-\frac{3y)/x-2-x^{-4} ?

The solution for (dy}{dx}=-\frac{3y)/x-2-x^{-4} is y=-x/2-(ln(x))/(x^3)+(c_{1})/(x^3)

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(dy}{dx}=-\frac{3y)/x-2-x^{-4}

\frac{d y}{d x} = - \frac{3 y}{x} - 2 - x^{- 4}

y = - \frac{x}{2} - \frac{ln ( x )}{x ^{3}} + \frac{c _{1}}{x ^{3}}

Solution steps

\frac{d y}{d x} = - \frac{3 y}{x} - 2 - x^{- 4}

Solve linear ODE:

y = - \frac{x}{2} - \frac{ln ( x )}{x ^{3}} + \frac{c _{1}}{x ^{3}}

y = - \frac{x}{2} - \frac{ln ( x )}{x ^{3}} + \frac{c _{1}}{x ^{3}}

\frac{1}{1 - x}, 3

\frac{d}{d x} (\frac{5}{1 - x})

\int \frac{1}{sec ^{2} ( y )} d y

\frac{d}{d x} ((4 - x^{\frac{2}{3}})^{3})

x \to - 8 lim (1 + - 2 x)

What is the solution for (dy}{dx}=-\frac{3y)/x-2-x^{-4} ?
The solution for (dy}{dx}=-\frac{3y)/x-2-x^{-4} is y=-x/2-(ln(x))/(x^3)+(c_{1})/(x^3)