What is the limit as x approaches-8 of 1+sqrt(-2x) ?

The limit as x approaches-8 of 1+sqrt(-2x) is 5

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limit as x approaches-8 of 1+sqrt(-2x)

x \to - 8 lim (1 + - 2 x)

5

Solution steps

x \to - 8 lim (1 + - 2 x)

Plug in the value

x = - 8

= 1 + - 2 (- 8)

Simplify

1 + - 2 (- 8) : 5

= 5

\frac{\partial}{\partial x} (x - 2)

\int y sin (x + y^{2}) d y

y^{^{'}} = 3 y t

\int_{0}^{5} f (x) d x

x \to 0 + lim (\frac{sin ( 2 x )}{x})

What is the limit as x approaches-8 of 1+sqrt(-2x) ?
The limit as x approaches-8 of 1+sqrt(-2x) is 5