What is integral from 0 to 5 of f(x) ?

The answer to integral from 0 to 5 of f(x) is (25f)/2

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integral from 0 to 5 of f(x)

\int_{0}^{5} f (x) d x

\frac{25 f}{2}

Solution steps

\int_{0}^{5} f x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= f \cdot \int_{0}^{5} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0}^{5}

= f [\frac{x ^{2}}{2}]_{0}^{5}

Compute the boundaries:

\frac{25}{2}

= f \frac{25}{2}

Simplify

= \frac{25 f}{2}

x \to 0 + lim (\frac{sin ( 2 x )}{x})

\int y^{2} (y + \frac{2}{3}) d y

f (x) = - 4 cos (2 x)

\int - \frac{1}{e ^{x}} d x

x \to - 2 lim (1 - x^{2})

What is integral from 0 to 5 of f(x) ?
The answer to integral from 0 to 5 of f(x) is (25f)/2