What is the tangent of f(x)=3x^2+2x,\at x=-3 ?

The tangent of f(x)=3x^2+2x,\at x=-3 is y=-16x-27

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tangent of f(x)=3x^2+2x,\at x=-3

tangent of

f (x) = 3 x^{2} + 2 x, at x = - 3

y = - 16 x - 27

Solution steps

Find the tangent point:

(- 3, 21)

Find the slope of

f (x) = 3 x^{2} + 2 x : \frac{df ( x )}{d x} = 6 x + 2

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 16

Find the line with slope m=

- 16

and passing through

(- 3, 21) : y = - 16 x - 27

y = - 16 x - 27

\frac{\partial}{\partial y} ((e^{x} - x) cos (y))

\int (sin (x) - 5 cos (x)) d x

x \to 1 lim (\frac{x}{x ^{2} + 1})

\frac{\partial}{\partial x} (e^{- 2 x^{2} - 5 y^{2}})

\int x y e^{x} d x

What is the tangent of f(x)=3x^2+2x,\at x=-3 ?
The tangent of f(x)=3x^2+2x,\at x=-3 is y=-16x-27