What is the derivative of sin(x)+1/9 cot(x) ?

The derivative of sin(x)+1/9 cot(x) is cos(x)-1/9 csc^2(x)

What is the first derivative of sin(x)+1/9 cot(x) ?

The first derivative of sin(x)+1/9 cot(x) is cos(x)-1/9 csc^2(x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

sin (x) + \frac{1}{9} cot (x)

cos (x) - \frac{1}{9} csc^{2} (x)

Solution steps

\frac{d}{d x} (sin (x) + \frac{1}{9} cot (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (sin (x)) + \frac{d}{d x} (\frac{1}{9} cot (x))

\frac{d}{d x} (sin (x)) = cos (x)

\frac{d}{d x} (\frac{1}{9} cot (x)) = - \frac{1}{9} csc^{2} (x)

= cos (x) - \frac{1}{9} csc^{2} (x)

\int \frac{2 x ^{5} + x}{x} d x

\int_{- 1}^{0} x d x

\frac{d y}{d x} = 7 y e^{x + 8}

\int_{4}^{\infty} e^{- 5 x} d x

\frac{d y}{d x} = \frac{e ^{x}}{1 + e ^{x}}

What is the derivative of sin(x)+1/9 cot(x) ?
The derivative of sin(x)+1/9 cot(x) is cos(x)-1/9 csc^2(x)
What is the first derivative of sin(x)+1/9 cot(x) ?
The first derivative of sin(x)+1/9 cot(x) is cos(x)-1/9 csc^2(x)