What is the derivative of 3+5cos(3t) ?

The derivative of 3+5cos(3t) is -15sin(3t)

What is the first derivative of 3+5cos(3t) ?

The first derivative of 3+5cos(3t) is -15sin(3t)

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derivative of

3 + 5 cos (3 t)

- 15 sin (3 t)

Solution steps

\frac{d}{d t} (3 + 5 cos (3 t))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (3) + \frac{d}{d t} (5 cos (3 t))

\frac{d}{d t} (3) = 0

\frac{d}{d t} (5 cos (3 t)) = - 15 sin (3 t)

= 0 - 15 sin (3 t)

Simplify

= - 15 sin (3 t)

x \to 6 lim (ln (7 - x))

\frac{\partial}{\partial x} (e^{x} tan (y))

x^{3} - 5 x^{2}

\frac{d}{d x} (4 x^{2})

y^{^{'}} = 13 t y - 8 t

What is the derivative of 3+5cos(3t) ?
The derivative of 3+5cos(3t) is -15sin(3t)
What is the first derivative of 3+5cos(3t) ?
The first derivative of 3+5cos(3t) is -15sin(3t)