What is the solution for y^'=13ty-8t ?

The solution for y^'=13ty-8t is y=(e^{(13t^2+c_{1})/2})/(13)+8/13

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'=13ty-8t

y^{^{'}} = 13 t y - 8 t

y = \frac{e ^{\frac{13 t ^{2} + c _{1}}{2}}}{13} + \frac{8}{13}

Solution steps

y^{'} (t) = 13 t y - 8 t

Solve separable ODE:

y = \frac{e ^{\frac{13 t ^{2} + c _{1}}{2}}}{13} + \frac{8}{13}

y = \frac{e ^{\frac{13 t ^{2} + c _{1}}{2}}}{13} + \frac{8}{13}

(x - 4)^{3} e^{- 4 x}

x^{2} + 6 x + 16, 2 x^{2} + 3 x - 2

\int 2 x^{2} sec^{2} (x^{3} + 1) d x

x \to 2 lim (sin (- 4 + x^{2}))

\frac{d}{d x} (\frac{x - 4}{x + 4})

What is the solution for y^'=13ty-8t ?
The solution for y^'=13ty-8t is y=(e^{(13t^2+c_{1})/2})/(13)+8/13