What is area x^2+6x+16,2x^2+3x-2 ?

The answer to area x^2+6x+16,2x^2+3x-2 is 243/2

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area x^2+6x+16,2x^2+3x-2

area

x^{2} + 6 x + 16, 2 x^{2} + 3 x - 2

\frac{243}{2}

Decimal

121.5

Solution steps

Apply the area formula:

\int_{- 3}^{6} x^{2} + 6 x + 16 - (2 x^{2} + 3 x - 2) d x

Solve

\int_{- 3}^{6} x^{2} + 6 x + 16 - (2 x^{2} + 3 x - 2) d x : \frac{243}{2}

The area is:

= \frac{243}{2}

\int 2 x^{2} sec^{2} (x^{3} + 1) d x

x \to 2 lim (sin (- 4 + x^{2}))

\frac{d}{d x} (\frac{x - 4}{x + 4})

f (x) = \frac{1 - x}{1 + x}, (2, - \frac{1}{3})

n = 1 \sum \infty \frac{n}{ln ( n + 1 )}

What is area x^2+6x+16,2x^2+3x-2 ?
The answer to area x^2+6x+16,2x^2+3x-2 is 243/2