What is the tangent of f(x)=(1-x)/(1+x),(2,-1/3) ?

The tangent of f(x)=(1-x)/(1+x),(2,-1/3) is y=-2/9 x+1/9

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tangent of f(x)=(1-x)/(1+x),(2,-1/3)

tangent of

f (x) = \frac{1 - x}{1 + x}, (2, - \frac{1}{3})

y = - \frac{2}{9} x + \frac{1}{9}

Solution steps

Find the slope of

f (x) = \frac{1 - x}{1 + x} : \frac{df ( x )}{d x} = - \frac{2}{( 1 + x ) ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{2}{9}

Find the line with slope m=

- \frac{2}{9}

and passing through

(2, - \frac{1}{3}) : y = - \frac{2}{9} x + \frac{1}{9}

y = - \frac{2}{9} x + \frac{1}{9}

n = 1 \sum \infty \frac{n}{ln ( n + 1 )}

\int 2 x^{17} e^{- x^{9}} d x

y^{^{'''}} - 5 y^{^{''}} + 6 y^{^{'}} = 2 sin (x) + 8

y = x^{6 c o s (x)}

\frac{\partial}{\partial x} (x^{2} + x e^{2} y - y)

What is the tangent of f(x)=(1-x)/(1+x),(2,-1/3) ?
The tangent of f(x)=(1-x)/(1+x),(2,-1/3) is y=-2/9 x+1/9