What is the integral of 2x^{17}e^{-x^9} ?

The integral of 2x^{17}e^{-x^9} is 2/9 (-e^{-x^9}x^9-e^{-x^9})+C

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integral of 2x^{17}e^{-x^9}

\int 2 x^{17} e^{- x^{9}} d x

\frac{2}{9} (- e^{- x^{9}} x^{9} - e^{- x^{9}}) + C

Solution steps

\int 2 x^{17} e^{- x^{9}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int x^{17} e^{- x^{9}} d x

Apply u-substitution

: \int \frac{e ^{- u^{\frac{9}{17}}} u ^{\frac{1}{17}}}{17} d u

= 2 \cdot \int \frac{e ^{- u^{\frac{9}{17}}} u ^{\frac{1}{17}}}{17} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \frac{1}{17} \cdot \int e^{- u^{\frac{9}{17}}} u^{\frac{1}{17}} d u

Apply u-substitution

: \int \frac{17 e ^{- v} v}{9} d v

= 2 \cdot \frac{1}{17} \cdot \int \frac{17 e ^{- v} v}{9} d v

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \frac{1}{17} \cdot \frac{17}{9} \cdot \int e^{- v} v d v

Apply Integration By Parts

: - e^{- v} v - \int - e^{- v} d v

= 2 \cdot \frac{1}{17} \cdot \frac{17}{9} (- e^{- v} v - \int - e^{- v} d v)

\int - e^{- v} d v = e^{- v}

= 2 \cdot \frac{1}{17} \cdot \frac{17}{9} (- e^{- v} v - e^{- v})

Substitute back

= 2 \cdot \frac{1}{17} \cdot \frac{17}{9} (- e^{- (x^{17})^{\frac{9}{17}}} (x^{17})^{\frac{9}{17}} - e^{- (x^{17})^{\frac{9}{17}}})

Simplify

2 \cdot \frac{1}{17} \cdot \frac{17}{9} (- e^{- (x^{17})^{\frac{9}{17}}} (x^{17})^{\frac{9}{17}} - e^{- (x^{17})^{\frac{9}{17}}}) : \frac{2}{9} (- e^{- x^{9}} x^{9} - e^{- x^{9}})

= \frac{2}{9} (- e^{- x^{9}} x^{9} - e^{- x^{9}})

Add a constant to the solution

= \frac{2}{9} (- e^{- x^{9}} x^{9} - e^{- x^{9}}) + C

y^{^{'''}} - 5 y^{^{''}} + 6 y^{^{'}} = 2 sin (x) + 8

y = x^{6 c o s (x)}

\frac{\partial}{\partial x} (x^{2} + x e^{2} y - y)

\frac{d}{d x} (\frac{( x + 1 ) ^{5}}{( 1 - x ) ^{4}})

y = ln (e^{3 x})

What is the integral of 2x^{17}e^{-x^9} ?
The integral of 2x^{17}e^{-x^9} is 2/9 (-e^{-x^9}x^9-e^{-x^9})+C