What is the derivative of 3x^2-4x-5 ?

The derivative of 3x^2-4x-5 is 6x-4

What is the first derivative of 3x^2-4x-5 ?

The first derivative of 3x^2-4x-5 is 6x-4

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\frac{d}{d x} (3 x^{2} - 4 x - 5)

6 x - 4

Solution steps

\frac{d}{d x} (3 x^{2} - 4 x - 5)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) - \frac{d}{d x} (4 x) - \frac{d}{d x} (5)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (5) = 0

= 6 x - 4 - 0

Simplify

= 6 x - 4

\frac{( - s - 1 )}{s ^{2} + s + 1}

\frac{d}{d x} (\frac{10}{x})

y^{^{'}} - \frac{3}{2} y = - \frac{3}{2} t

\frac{d}{d x} (x e^{- 10 x})

\frac{\partial}{\partial x} (2 x^{2} y^{3})

What is the derivative of 3x^2-4x-5 ?
The derivative of 3x^2-4x-5 is 6x-4
What is the first derivative of 3x^2-4x-5 ?
The first derivative of 3x^2-4x-5 is 6x-4