What is the derivative of 3sin(1+cos(4x^2)) ?

The derivative of 3sin(1+cos(4x^2)) is 6cos(4)xcos(1+cos(4)x^2)

What is the first derivative of 3sin(1+cos(4x^2)) ?

The first derivative of 3sin(1+cos(4x^2)) is 6cos(4)xcos(1+cos(4)x^2)

Popular >

\frac{d}{d x} (3 sin (1 + cos (4) x^{2}))

6 cos (4) x cos (1 + cos (4) x^{2})

Solution steps

\frac{d}{d x} (3 sin (1 + cos (4) x^{2}))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} (sin (1 + cos (4) x^{2}))

Apply the chain rule:

cos (1 + cos (4) x^{2}) \frac{d}{d x} (1 + cos (4) x^{2})

= cos (1 + cos (4) x^{2}) \frac{d}{d x} (1 + cos (4) x^{2})

\frac{d}{d x} (1 + cos (4) x^{2}) = 2 cos (4) x

= 3 cos (1 + cos (4) x^{2}) \cdot 2 cos (4) x

Simplify

= 6 cos (4) x cos (1 + cos (4) x^{2})

\int_{0}^{t} t^{2} e^{- \frac{t}{3}} d t

y = \frac{5}{x}, (5, 1)

\int_{1}^{8} (\frac{2}{x}) d x

f (x) = x^{3}, at x = 3

\int - 2 x e^{- \frac{1}{2} x} d x

What is the derivative of 3sin(1+cos(4x^2)) ?
The derivative of 3sin(1+cos(4x^2)) is 6cos(4)xcos(1+cos(4)x^2)
What is the first derivative of 3sin(1+cos(4x^2)) ?
The first derivative of 3sin(1+cos(4x^2)) is 6cos(4)xcos(1+cos(4)x^2)