What is the tangent of f(x)=x^3,\at x=3 ?

The tangent of f(x)=x^3,\at x=3 is y=27x-54

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tangent of f(x)=x^3,\at x=3

tangent of

f (x) = x^{3}, at x = 3

y = 27 x - 54

Solution steps

Find the tangent point:

(3, 27)

Find the slope of

f (x) = x^{3} : \frac{df ( x )}{d x} = 3 x^{2}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 27

Find the line with slope m=

27

and passing through

(3, 27) : y = 27 x - 54

y = 27 x - 54

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\int \frac{2 x}{x ^{4} + 1} d x

\int 5 x^{2} a^{2} - x^{2} d x

What is the tangent of f(x)=x^3,\at x=3 ?
The tangent of f(x)=x^3,\at x=3 is y=27x-54