What is the integral of sec(x)cos(x) ?

The integral of sec(x)cos(x) is x+C

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integral of sec(x)cos(x)

\int sec (x) cos (x) d x

x + C

Solution steps

\int sec (x) cos (x) d x

Express with sin, cos

= \int 1 d x

Integral of a constant:

\int a d x = a x

= 1 \cdot x

Simplify

= x

Add a constant to the solution

= x + C

y^{^{'''}} + 9 y^{^{'}} = 0

\frac{1}{( s - 1 ) ^{2} ( s + 1 )}

f (x) = \frac{1}{1 - x}, at x = 2

\frac{d y}{d t} = y - 4 t + (y - 4 t)^{2} + 4

\int x (2 x^{2} + 1)^{5} d x