What is the solution for y^{''}+16y=cos(4x)+sin(4x) ?

The solution for y^{''}+16y=cos(4x)+sin(4x) is y=c_{1}cos(4x)+c_{2}sin(4x)+(xsin(4x))/8-(xcos(4x))/8

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y^{''}+16y=cos(4x)+sin(4x)

y^{^{''}} + 16 y = cos (4 x) + sin (4 x)

y = c_{1} cos (4 x) + c_{2} sin (4 x) + \frac{x sin ( 4 x )}{8} - \frac{x cos ( 4 x )}{8}

Solution steps

y^{''} (x) + 16 y = cos (4 x) + sin (4 x)

Solve linear ODE:

y = c_{1} cos (4 x) + c_{2} sin (4 x) + \frac{x sin ( 4 x )}{8} - \frac{x cos ( 4 x )}{8}

y = c_{1} cos (4 x) + c_{2} sin (4 x) + \frac{x sin ( 4 x )}{8} - \frac{x cos ( 4 x )}{8}

\int + \frac{x ^{2}}{1 - 2 x ^{3}} d x

n = 0 \sum \infty \frac{( n - 1 )}{n}

\int_{1}^{3} (x^{2} - 4 x + 3) d x

\frac{d}{d x} (2 x^{2} - 7 x)

\int \frac{x ^{2}}{e ^{7 x}} d x

What is the solution for y^{''}+16y=cos(4x)+sin(4x) ?
The solution for y^{''}+16y=cos(4x)+sin(4x) is y=c_{1}cos(4x)+c_{2}sin(4x)+(xsin(4x))/8-(xcos(4x))/8