What is the derivative of 2e^x-3x^e+sqrt(e) ?

The derivative of 2e^x-3x^e+sqrt(e) is -3ex^{e-1}+2e^x

What is the first derivative of 2e^x-3x^e+sqrt(e) ?

The first derivative of 2e^x-3x^e+sqrt(e) is -3ex^{e-1}+2e^x

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Popular >

\frac{d}{d x} (2 e^{x} - 3 x^{e} + e)

- 3 e x^{e - 1} + 2 e^{x}

Solution steps

\frac{d}{d x} (2 e^{x} - 3 x^{e} + e)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 e^{x}) - \frac{d}{d x} (3 x^{e}) + \frac{d}{d x} (e)

\frac{d}{d x} (2 e^{x}) = 2 e^{x}

\frac{d}{d x} (3 x^{e}) = 3 e x^{e - 1}

\frac{d}{d x} (e) = 0

= 2 e^{x} - 3 e x^{e - 1} + 0

Simplify

= - 3 e x^{e - 1} + 2 e^{x}

x \to 0 lim (\frac{2 + sin ( x )}{x})

\int 2 x + 5 d x

x \frac{d y}{d x} + y = 4 x + 1, y (1) = 8

x \to 6 lim (x - 5)

\int (x + 1) d x

What is the derivative of 2e^x-3x^e+sqrt(e) ?
The derivative of 2e^x-3x^e+sqrt(e) is -3ex^{e-1}+2e^x
What is the first derivative of 2e^x-3x^e+sqrt(e) ?
The first derivative of 2e^x-3x^e+sqrt(e) is -3ex^{e-1}+2e^x