What is area y= 25/2-(x^2)/2 ,(-5,5) ?

The answer to area y= 25/2-(x^2)/2 ,(-5,5) is 250/3

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area y= 25/2-(x^2)/2 ,(-5,5)

area

y = \frac{25}{2} - \frac{x ^{2}}{2}, (- 5, 5)

\frac{250}{3}

Decimal

83.33333 \dots

Solution steps

Apply the area formula:

\int_{- 5}^{5} \frac{25}{2} - \frac{x ^{2}}{2} d x

Solve

\int_{- 5}^{5} \frac{25}{2} - \frac{x ^{2}}{2} d x : \frac{250}{3}

The area is:

= \frac{250}{3}

\frac{d}{d x} (5 - 3 x)

20 t^{3}

y = sin^{2} (x^{2})

\frac{\partial}{\partial x} (ln (4 x^{2} + y^{2} + 2))

\int \frac{x ^{2}}{2} - \frac{2}{x ^{2}} d x

What is area y= 25/2-(x^2)/2 ,(-5,5) ?
The answer to area y= 25/2-(x^2)/2 ,(-5,5) is 250/3