What is (\partial)/(\partial x)(xy+yz+xz) ?

The answer to (\partial)/(\partial x)(xy+yz+xz) is y+z

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(\partial)/(\partial x)(xy+yz+xz)

\frac{\partial}{\partial x} (x y + yz + x z)

y + z

Solution steps

\frac{\partial}{\partial x} (x y + yz + x z)

Treat

y, z

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x y) + \frac{\partial}{\partial x} (yz) + \frac{\partial}{\partial x} (x z)

\frac{\partial}{\partial x} (x y) = y

\frac{\partial}{\partial x} (yz) = 0

\frac{\partial}{\partial x} (x z) = z

= y + 0 + z

Simplify

= y + z

y^{^{''}} - 4 y^{^{'}} + 4 y = 2 + 8 x - 4 x^{2}

(- 1, - 2), (0, 5)

\frac{d}{d x} (\frac{1 - 4 e ^{x}}{1 - 5 cos ( x )})

f (x) = \frac{1}{2} arctan (\frac{x}{2})

\frac{d}{d x} (6 x^{2} - 96 x)

What is (\partial)/(\partial x)(xy+yz+xz) ?
The answer to (\partial)/(\partial x)(xy+yz+xz) is y+z