What is the derivative of (64x/(x^2+64)) ?

The derivative of (64x/(x^2+64)) is (64(-x^2+64))/((x^2+64)^2)

What is the first derivative of (64x/(x^2+64)) ?

The first derivative of (64x/(x^2+64)) is (64(-x^2+64))/((x^2+64)^2)

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\frac{d}{d x} (\frac{64 x}{x ^{2} + 64})

\frac{64 ( - x ^{2} + 64 )}{( x ^{2} + 64 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{64 x}{x ^{2} + 64})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 64 \frac{d}{d x} (\frac{x}{x ^{2} + 64})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= 64 \cdot \frac{\frac{d x}{d x} ( x ^{2} + 64 ) - \frac{d}{d x} ( x ^{2} + 64 ) x}{( x ^{2} + 64 ) ^{2}}

\frac{d x}{d x} = 1

\frac{d}{d x} (x^{2} + 64) = 2 x

= 64 \cdot \frac{1 \cdot ( x ^{2} + 64 ) - 2 xx}{( x ^{2} + 64 ) ^{2}}

Simplify

64 \cdot \frac{1 \cdot ( x ^{2} + 64 ) - 2 xx}{( x ^{2} + 64 ) ^{2}} : \frac{64 ( - x ^{2} + 64 )}{( x ^{2} + 64 ) ^{2}}

= \frac{64 ( - x ^{2} + 64 )}{( x ^{2} + 64 ) ^{2}}

\int 4 (1 + tan^{2} (x)) d x

y^{^{''}} + 2 y^{^{'}} = 2 x + 5 - e^{-} 2 x

\frac{d}{d x} (\frac{2 x ^{3} - 7}{x ^{2}})

\frac{d y}{d x} = 100 - y

x \to \infty lim ((1 + \frac{1}{2 x + 1})^{x^{2 - 3}})

What is the derivative of (64x/(x^2+64)) ?
The derivative of (64x/(x^2+64)) is (64(-x^2+64))/((x^2+64)^2)
What is the first derivative of (64x/(x^2+64)) ?
The first derivative of (64x/(x^2+64)) is (64(-x^2+64))/((x^2+64)^2)